Find the maximum or minimum values of the function y = x + (1/x) for x>0. Share with your friends Share 0 Manbar Singh answered this We have, y = x + 1xdifferentiating both sides with respect to x, we getdydx = 1 - 1x2For maxima or minima, dydx = 0⇒1 - 1x2 = 0⇒x2 - 1 = 0⇒x-1x+1 = 0⇒x-1 = 0 or x+1 = 0⇒x = 1 or x = -1rejected, as x>0Now,d2ydx2 = ddxdydx = ddx1 - 1x2 = 2x3Now,d2ydx2x=1 = 213 = 2 > 0 So, y is minimum at x = 1 Minimum value of y = 1 + 11 = 1 + 1 = 2 1 View Full Answer