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kittyme1 asked this question on Class IX » Math » Quadrilaterals

find the measure of each angle of a parallelogram, if one of its angle is 30 degree less than twice of the smallest angle.

Asked by kittyme1(student), on 5/3/11
Answers

Hi!
Here is the answer to your question.
Let ∠A be the smallest angle of the parallelogram ABCD
∠A = ∠C (opposite angles of parallelogram are equal)
∠B = ∠D (opposite angles of parallelogram are equal)
Given, ∠B = 2∠A – 30°
∠A + ∠B = 180° (sum of consecutive interior angles is supplementary)
⇒ ∠A + (2∠A – 30°) = 180°
⇒ 3∠A = 210°
⇒∠A = 70
∴∠B = 2 × 70° – 30° = 140° – 30° = 110°
Thus, ∠A = ∠C = 70° and ∠B = ∠D = 110°
Cheers!

 
Posted by Lalit Mehra(MeritNation Expert), on 9/3/11
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