find the number of diagonals in an octagon?
Number Of Diagonals Of Polygon = n(n-3) / 2
Where n Is Number Of Sides
Here n = 8
Substitute Values
We Have
Diagonals= 8*5/2 = 20
So A Octagon Has 20 Diagonals
find the number of diagonals in an octagon?
Number Of Diagonals Of Polygon = n(n-3) / 2
Where n Is Number Of Sides
Here n = 8
Substitute Values
We Have
Diagonals= 8*5/2 = 20
So A Octagon Has 20 Diagonals