find the values of using suitable identity 103 cube
Hi Pramath,
you can use IDENTITY NO:- 6 that is, (x+y)3 = x3 + y3+ 3x2y + 3xy2
so, x= 100
y=3
therefore,(100)3+ (3)3+ 3* (100)2* 3 + 3*100* (3)2
= 1000000+27+90000+2700 = 1092727
and for checking,
(103)3=103 * 103 * 103 =10609 * 103 = 1092727