find the values of using suitable identity 103 cube

Hi Pramath,

you can use IDENTITY NO:- 6 that is, (x+y)3 = x3 + y3+ 3x2y + 3xy2

so, x= 100

y=3

therefore,(100)3+ (3)3+ 3* (100)2* 3 + 3*100* (3)2

= 1000000+27+90000+2700 = 1092727

and for checking,

(103)3=103 * 103 * 103 =10609 * 103 = 1092727

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