find the zeroes of the polynomial: x4 - 2 x2 a2 + a4 Share with your friends Share 0 Ashutosh Verma answered this Answer : We have : x 4 - 2 x2 a2 + a4 , So ⇒x22 + a22 - 2 × x2 × a2⇒x2 -a2 2 So, Zeros : ⇒x2 -a2 2 = 0 ⇒x2 -a2 = 0 ⇒x2 = a2 ⇒x = ± a So, ⇒x = a and - a ( Ans ) 0 View Full Answer