From a uniform disc of Radius R and mass 9kg, a small disc of radius r/3 is removed from disc concentrically. What will be the moment of inertia of remaining disc, passing through the centre and perpendicular to its plane ?

Initially mass of the disc is m and radisu of the disc is r.Initial moment of inertia i = 12mr2When radius r/3 part is cut from the disc and is taken out.Mass of the this part is given by:πr2 has mass = mπ(r/3)2 has mass = mπr2π(r/3)2  = m9Mass of the remaining part is m -m9 = m10Moment of inertia of the remainf part abou the centre of the  disc and perpendicular to the plane is:I' = 12m10r2I' = I10

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