From an external point P, tangents PA and PB  are drawn to a circle of radius 5 units with centre O , where A and B are the points on the circle . If PA = 12 units then find:
 (A) area of quadrilateral PAOB
 (B) area of triangle PAB
(C) radius of circumcircle of triangle PAB

Hi,


here OA= OB = 5 and PA=PB= 12OP= 52+122= 13so area of PAOB = 2×area of triangle PAO= 2×12×5×12= 60 SQUARE UNIT now since OA= 5 so using pythagrus triplet OM = 3 and AM = 4 so PM= 13-3 = 10So area of PAB = 12×AB×PM=12×8×10 = 40 square unitnow since angle A+angle B= 180 = angle APB+angle AOBhence circum center of triangle APB will pass through O. So OP will be diameter and hence radius = 132= 6.5 unitRegards
 

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