give possible expression for the length and breadth of a rectangle whose area is 4a^2+4a-3

Answer :

We have Area of rectangle  =   4a2 +  4a  -  3 

So,

  4a2 + 6a -  2a  -  3 

  2a ( 2a  +  3 ) - 1 (  2a  +  3   )

  ( 2a  -  1 ) ( 2a  +  3 ) 

And

We know Area of rectangle  =  Length × Breadth 

So,
Possible expression for the length and breadth of a rectangle  = ( 2a  -  1 )  and  ( 2a  +  3 )                              ( Ans )

  • 1
4a2+4a-3

= 4a2+6a-2a-3

=2a(2a+3) -1(2a+3)

=(2a+3)(2a-1)

Therefore, the possible expressions for the length and breadth are (2a+3) and (2a-1) respectively.

 
  • -1
first we have to factorize the expression.
4a2+4a-3
=>4a2+6a-2a-3
=>2a(2a+3)-1(2a+3)
=>(2a-1)(2a+3)​

therefore,length=2a+3 & breadth=2a-1
  • 0
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