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HCF of three numbers taken pairwise is 2 . if the LCM of three numbers is 59976,then the product of the three numbers taken together will be..?

Asked by Kavita Karki(student) , on 29/11/12

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Product of  n  numbers = L.C.M of  n  numbers × (H.C.F of each pair) ( n  – 1)

  Product of 3 numbers = L.C.M of 3 numbers × (H.C.F of each pair)2

= 59976 × 22 = = 59976 × 4 = 239904


Posted by Tushar Kohli(MeritNation Expert)on 29/11/12

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