Purchase mobileappIcon Download our Mobile App
Call Us at 011-40705070   or  
Click to Call
Select your Board & Class
  • Select Board
  • Select Class

HCF of three numbers taken pairwise is 2 . if the LCM of three numbers is 59976,then the product of the three numbers taken together will be..?

Asked by Kavita Karki(student) , on 29/11/12



Product of n numbers = L.C.M of n numbers × (H.C.F of each pair)( n – 1)

Product of 3 numbers = L.C.M of 3 numbers × (H.C.F of each pair)2

= 59976× 22= = 59976 × 4 = 239904

Posted by Tushar Kohli(MeritNation Expert)on 29/11/12

This conversation is already closed by Expert

Ask a QuestionHave a doubt? Ask our expert and get quick answers.
Show me more questions