011-40705070  or  
Call me
Download our Mobile App
Select Board & Class
  • Select Board
  • Select Class
Rima Bareh from St.Anthony's Higher Secondary School , asked a question
Subject: Math , asked on 13/9/12

 help plz !!!

integration of sec x log(sec x + tan x) dx 

Certified by MeritNation Expert

BEST ANSWER

Mohd Imad , From Gems Our Own English High School , added an answer
Answered on 14/9/12

Ans : I =  ⌡ secx*log(secx+tanx) dx

Let u=log(secx+tanx)

Differentiate wrt  "x"

du/dx = {1/(secx+tanx)} * { d(secx)/dx + d(tanx)/dx}

du/dx = {1/(secx+tanx)} * { (secx*tanx)+(sec2x)}

du/dx = {1/(secx+tanx)} * { (tanx)+(secx)} * secx

du = secx dx

Therefore: I = ⌡u du

I = (u2/2) + C

I = ( [ log(secx+tanx)]  2/2) + C

If you are satified do give thumbs up.

This conversation is already closed by Expert

View More