How is H'= -vh/u
If h is the height of the object and h ′ is the height of the image, then the magnification m produced by a spherical mirror is given by :
m = h'/h ........(1)
The magnification m is also related to the object distance (u) and image distance (v). It can be expressed as:
m = -v/u ........(2)
From eq. 1 and eq. 2, we get :
h'/h = -v/u
hence, h' = - h
m = h'/h ........(1)
The magnification m is also related to the object distance (u) and image distance (v). It can be expressed as:
m = -v/u ........(2)
From eq. 1 and eq. 2, we get :
h'/h = -v/u
hence, h' = - h