How much pure alcohol must be added to 400 ml of a 15% solution to make its strength 32%?
Original amount of alcohol = 400 ml
Percentage of alcohol in the solution = 15%
Let x ml alcohol is added to the solution
∴ Amount of alcohol = (60 + x) ml
Amount of solution = (400 + x) ml
Given that the percentage of alcohol in the solution is 32%
Thus, approximately 179.4 ml of alcohol is added to the solution.
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