how shall i factorise:
(x+y)3 +x+y
??
(x + y)3+ x + y = (x + y)3 + (x + y)
= (x + y)[(x + y)2 + 1]
= (x + y)[x 2 + y 2 + 2xy + 1]
What are you looking for?
how shall i factorise:
(x+y)3 +x+y
??
(x + y)3+ x + y = (x + y)3 + (x + y)
= (x + y)[(x + y)2 + 1]
= (x + y)[x 2 + y 2 + 2xy + 1]