hOW TO FIND ANTILOG AND LOG FROM THE LOG TABLE??
PLS REPLY SOON
Dear Student,
Let us understand log calculation, with the help of an example.
Suppose we have to find log of 3.352 x 1011.
Taking log,
log(3.352 x 1011) = log (3.352) + log(1011)
log(3.352 x 1011) = log(3.352) + 11 log(10)
log(3.352 x 1011) = log(3.352) + 11
To find log(3.352), we will look for the value in 33th row, 5th column, which is 5250. To this we add the mean difference of the 2nd column, in the same row, in the log table.
5250 + 3 = 5253.
Now, log(3.352) = 0.5253
So, log(3.352 x 1011) = 11+0.5253 = 11.5253
Let us now, take antilog of 11.5253.
The digits before the decimal becomes the mantissa.
antilog(11.5253) = antilog(0.5253) x 1011
To find the value of antilog(0.5253), we will look for the value in 0.52th row, 5th column, which is 3350. To this value add the mean difference of 3rd column, in the same row, in the antilog table.
3350+2=3352
Therefore, antilog(0.5253)=3.352.
So, antilog(11.5253) = 3.352 x 1011.
Hope, its clear now.
Enjoy learning!!