i want derivation of cp and cv for monoatomic, diatomic, triatomic..... plz answer fast its urgent 2morrow is my exam..
Please refer the answer posted by Aman.
Similarly you can for diatomic and tri atomic gas gases.
Diatomic gas has 5 degrees of freedom and tri atomic gas has 6 degrees of freedom.
@ Aman - Good effort keep it up!!
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For Monoatomic gases
No of degrees are 3.All Three are translational energies
Hence the total internal energy for 1 mole of gas is
U=(1/3KBT+. 1/3KBT+1/3KBT)NA (Acc to law of equipartition law)(K=boltzman constant)
diff. it both sides w.r.t. T
therefore Cv =3/2R
Similarly you can solve for Diatomic gases but it has 5 degree of freedom.
By definition of Specific heat
by first law of thermodynamics
at constant volume (dW=0) then
But U=fµRT/2, so that
Then molar specific heat at constant volume,
now, rate of molar specific heat,
Cp/Cv=Γ (Γ is gamma)
█ For monoatomic gas (f=3)
█ For diatomic gas (f=5)
█ For Triatomic gas
▄Linear Structural (f=7)
▄non-linear structural (f=6)
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