I wnat divisibility test from 1 to 50. Plz answer as soon as possible..........
No special condition. Any integer is divisible by 1.
Division by 2:
If the number ends in 0, 2, 4, 6, or 8, then the number is divisible by 2. This is equivalent to being an even number.
Division by 3:
Add up all of the digits in the number. If the sum of the digits is divisible by 3, then so is the number.
example 327 = 3 + 2 + 7 = 12 that is divisible by 3 so 327 also divisible by 3
Division by 4:
If the last two digits of the number is divisible by 4 then so is the number.
Example, the number 93548 is divisible by 4 since 48 is divisible by 4.
Division by 5:
If the last digit is 0 or 5 then the number can be divided by 5.
Division by 6:
Apply the rule for 2 and 3. If the number passes both tests, then the number is divisible by 6.
Division by 7:
Double the last digit and subtract it from the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 7, then so is the larger number. If this smaller number is not divisible by 7, then neither is the larger number.
Example, let's check the divisibility of 864503:
864503, 3x2 = 6 and 86450-6 = 86444
86444, 4x2 = 8 and 8644-8 = 8636
8636, 6x2 = 12 and 863-12 = 851
851, 1x2 = 2 and 85-2 = 83
Since 83 is not divisible by 7, neither is the original number 864503.
Division by 8:
Check the last three digits of the number. If it forms an integer that is divisible by 8, then the number is also divisible by 8. For instance, 73540665742 is not divisible by 8 since 742 is not divisible by 8.
Division by 9:
Add up all of the digits in the number. If the sum of the digits is divisible by 9, then so is the number.
Division by 10:
If the last digit is 0, then the number is divisible by 10.
Division by 11:
Alternately add and subtract all of the digits of the number, starting with subtraction on the second digit. If the result is 0 or any number divisible by 11, then so is the number. For example, consider the number 119637360799. If we compute
1-1+9-6+3-7+3-6+0-7+9-9
we get a total of -11. Since -11 is divisible by 11, so is 119637360799.
Division by 12:
Apply the rules for 3 and 4. If the number passes both tests, then the number is divisible by 12.
Division by 13:
Multiply the last digit by 9 and subtract it from the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 13, then so is the larger number. If this smaller number is not divisible by 13, then neither is the larger number.
Example, let's check the divisibility of 399074:
399074, 4x9 = 36 and 39907-36 = 39871
39871, 1x9 = 9 and 3987-9 = 3978
3978, 8x9 = 72 and 397-72 = 325
325, 5x9 = 45 and 32-45 = -13
Since -13 divisible by 13, then 399074 is also divisible by 13.
Division by 14:
Apply the rule for 2 and one of the rules for 7. If the number passes both divisibility tests, then the number can be divided by 14.
Division by 15:
Apply the rules for 3 and 5. If the number passes both tests, then the number is divisible by 15.
Division by 16:
Check the last 4 digits of the number. If the last 4 digits form an integer that is divisible by 16, then the original number is also divisible by 16.
Example 157675552 can be divided by 16 since 5552 is a multiple of 16.
Division by 17:
Multiply the last digit by 5 and subtract it from the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 17, then so is the larger number. If this smaller number is not divisible by 17, then neither is the larger number.
Example, let's check the divisibility of 521172:
521172, 2x5 = 10 and 52117-10 = 52107
52107, 7x5 = 35 and 5210-35 = 5175
5175, 5x5 = 25 and 517-25 = 492
492, 2x5 = 10 and 49-10 = 39
Since 39 is not divisible by 17, then neither is 521172.
Division by 18:
Apply the rules for 2 and 9. If the number passes both tests, it is divisible by 18.
Division by 19:
Multiply the last digit by 2 and add it to the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 19, then so is the larger number. If this smaller number is not divisible by 19, then neither is the larger number.
Example, let's check the divisibility of 12483:
12483, 3x2 = 6 and 1248+6 = 1254
1254, 4x2 = 8 and 125+8 = 133
133, 3x2 = 6 and 13+6 = 19
Since 19 is divisible by 19, then so is 12483.
Division by 20:
Apply the rules for 4 and 5. If the number passes both tests, it is divisible by 20.
Division by 21:
Apply the rule for 3 and one of the rules for 7. If the number passes both tests, it is divisible by 21.
Division by 22:
Apply the divisibility tests for 2 and 11. If the number meets both conditions, it is divisible by 22.
Division by 23:
Multiply the last digit by 7 and add it to the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 23, then so is the larger number. If this smaller number is not divisible by 23, then neither is the larger number.
Example, let's check the divisibility of 53682:
53682, 2x7 = 14 and 5368+14 = 5382
5382, 2x7 = 14 and 538+14 = 552
552, 2x7 = 14 and 55+14 = 69
69, 9x7 = 63 and 6+63 = 69
Division by 24:
Apply the tests for 3 and 8. If the number passes both tests, then the number is a multiple of 24.
Division by 25:
If the last two digits are 00, 25, 50, or 75, then the number can be divided by 25.
Division by 26:
Apply the rule for 2 and one of the rules for 13. If the number passes both tests, it is divisible by 26.
Division by 27:
Multiply the last digit by 8 and subtract it from the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 27, then so is the larger number. If this smaller number is not divisible by 27, then neither is the larger number.
Example, let's check the divisibility of 10962:
10962, 2x8 = 16 and 1096-16 = 1080
1080, 0x8 = 0 and 108-0 = 108
108, 8x8 = 64 and 10-64 = -54
Since -54 is divisible by 27, 10962 is also divisible by 27.
Division by 28:
Apply the rule for 4 and one of the rules for 7. If the number passes both tests, it is divisible by 28.
Division by 29:
Multiply the last digit by 3 and add it to the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisiblity you know. If this smaller number is divisible by 29, then so is the larger number. If this smaller number is not divisible by 29, then neither is the larger number.
Example, let's check the divisibility of 24273:
24273, 3x3 = 9 and 2427+9 = 2436
2436, 6x3 = 18 and 243+18 = 261
261, 1x3 = 3 and 26+3 = 29
Since 29 is divisible by 29, then 24273 is as well.
Division by 30:
Apply the rules for 2, 3, and 5. If the number passes all three tests, then it is divisible by 30.
Division by 31:
Multiply the last digit by 3 and subtract it from the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 31, then so is the larger number. If this smaller number is not divisible by 31, then neither is the larger number.
Example, let's check the divisibility of 504273:
504273, 3x3 = 9 and 50427-9 = 50418
50418, 8x3 = 24 and 5041-24 = 5017
5017, 7x3 = 21 and 501-21 = 480
480, 0x3 = 0 and 48-0 = 48
Since 48 is not divisible by 31, then neither is 504273.
Division by 32:
Check the last 5 digits of the number. If the last 5 digits form an integer that is divisible by 32, then the original number is also divisible by 32.
Example 31999968 is divisible by 32 since 99968 is a multiple of 32.
Division by 33:
Apply the rule for 3 and one of the rules for 11. If the number passes both tests, it is divisible by 33.
Division by 34:
Apply the rule for 2 and one of the rules for 17. If the number passes both tests, it is divisible by 34.
Division by 35:
Apply the rules for 5 and 7. If the number passes both tests, it is divisible by 35.
Division by 36:
Apply the rules for 4 and 9. If the number passes both tests, it is divisible by 36.
Division by 37
Take the last three digits of the number and add this to the number formed by the remaining digits. Repeat this process until you end up with a number that has at most three digits. If the remaining number is divisible by 37, then so is the larger number.
Example, let's test the divisibility of 361975218:
361975218, 361975+218 = 362193
362193, 362+193 = 555
Since 555 is divisible by 37, then 361975218 is also divisible by 37.
Division by 38:
Apply the rules for 2 and 19. If the number passes both tests, it is divisible by 38.
Division by 39:
Apply the rule for 3 and one of the rules for 13. If the number passes both tests, it is divisible by 39.
Division by 40:
Apply the rules for 5 and 8. If the number passes both tests, it is divisible by 40.
Division by 41:
Multiply the last digit by 4 and subtract it from the number formed by the remaining digits. Repeat this process until you arrive at a smaller number whose divisibility you know. If this smaller number is divisible by 41, then so is the larger number. If this smaller number is not divisible by 41, then neither is the larger number.
Example, let's check the divisibility of 142311:
142311, 1x4 = 4 and 14231-4 = 14227
14227, 7x4 = 28 and 1422-28 = 1394
1394, 4x4 = 16 and 139-16 = 123
123, 3x4 = 12 and 12-12 = 0
Since 0 is divisible by 41, then so is 142311.
Division by 42:
Apply the rules for 6 and 7. If the number passes both tests, it is divisible by 42.
Division by 43:
Add thirteen times the last digit to the remaining leading truncated number. If the result is divisible by 43, then so was the first number. Apply this rule over and over again as necessary.
Example: 3182-->318+13*2=344-->34+13*4=86 which is recognisably twice 43, and so 3182 is also divisible by 43.
Division by 44:
Apply the rules for 4 and 11. If the number passes both tests, it is divisible by 44.
Division by 45:
Apply the rules for 5 and 9. If the number passes both tests, it is divisible by 45.
Division by 46:
Apply the rules for 2 and 23. If the number passes both tests, it is divisible by 45.
Division by 47:
Subtract fourteen times the last digit from the remaining leading truncated number. If the result is divisible by 47, then so was the first number. Apply this rule over and over again as necessary.
Example: 34827-->3482-14*7=3384-->338-14*4=282-->28-14*2=0 , remainder is zero and so 34827 is divisible by 47.
Division by 48:
Apply the rules for 3 and 16. If the number passes both tests, it is divisible by 48.
Division by 49:
Add 5 times the last digit to the rest.
Example : 1,127: 112+(7×5)=147.
147: 14 + (7×5) = 49
So 49 is divisible by 49 so 1127 also divisible by 49
Division by 50:
The last two digits are 00 or 50.