if ( 2sinteta + 3cos teta ) = 2 show that ( 3cos teta - 2 sin teta) = +/- 3 Share with your friends Share 0 Manbar Singh answered this We have, 2 sin θ + 3 cos θ = 2⇒2 sin θ + 3 cos θ2 = 4⇒4sin2θ + 9cos2θ + 12 sin θ cos θ = 4⇒41-cos2θ + 91-sin2θ + 12 sin θ cos θ = 4⇒4 - 4 cos2θ + 9 - 9 sin2θ + 12 sin θ cos θ = 4=-4 cos2θ - 9sin2θ + 12 sin θ cos θ = 4 - 4 - 9⇒4 cos2θ + 9 sin2θ - 12 sin θ cos θ = 9⇒2 cos θ - 3 sin θ2 = 9⇒2 cos θ - 3 sin θ = ±3 2 View Full Answer