if a=2, b=3 then find the value of : a) (a^b+b^a)^-1 b)(a^a+b^b)^-1 - Maths - Polynomials

Question

if a=2, b=3 then find the value of : a) (a^b+b^a)^-1 b)(a^a+b^b)^-1

Anuradha Sharma · Accepted Answer

a)ab+ba-1= 1ab+ba=123+32=18+9=117b)aa+bb-1= 1aa+bb=122+33=14+27=131

if a=2, b=3 then find the value of : a) (a^b+b^a)^-1 b)(a^a+b^b)^-1.