if a=2, b=3 then find the value of : a) (a^b+b^a)^-1 b)(a^a+b^b)^-1. can you pls.. answer it fast. Share with your friends Share 0 Anuradha Sharma answered this a)ab+ba-1= 1ab+ba=123+32=18+9=117b)aa+bb-1= 1aa+bb=122+33=14+27=131 0 View Full Answer