if (A+B) =45 then prove that

[1 ] . (1+tan A)(1+tan B) = 2

[2]. (cot A -1)(cot B -1) = 2

(A+B) = 45

tan(A+B) = tan45

tanA + tanB / 1 - tanAtanB = 1 

tanA + tanB = 1 - tanAtanB 

tanA + tanB + tanAtanB = 1..........[1]

now (1+tanA)(1+tanB) = 1 + [tanB + tanA + tanAtanB] 

                                     = 1+1 ...........[ from 1 ] 

                                     = 2.

                                     hence proved..

similarly u can get d second one also.......