if a + b+ c=0 then a3 +b3+c3 is equal to what

 using a3 + b3 + c3 - 3abc = ( a + b + c ) ( a2 + b2 + c2 - ab - bc - ca )

here if a+b+c = 0 then the answer will be 3abc                                                                                                                       because in RHS ( a + b + c ) becomes 0(zero) in multiplying the whole becomes 0. and when transposing -3abc it becomes +3abc. so here it becomes

a3 + b3 + c3 = 3abc 

hope u r clear wid it!! :D

  • 37

and plz explain the sum

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