if alpha +beta are the zeros of the polynomial kx2 +4x+4.  and alphasquare + beta square  = 24 .... find k

 

Hi!
Here is the answer to your question.
 
Given, α and β are the zeroes of the given polynomial kx2 + 4x + 4.
⇒ 24k2 + 8k – 16 = 0
⇒ 3k2 + k – 2 = 0
⇒ 3k2 + 3k – 2k – 2 = 0
⇒ 3k (k + 1) –2 (k + 1) = 0
⇒ (3k – 2) (k + 1) = 0
⇒ 3k – 2 = 0 or k + 1 = 0

Cheers!

  • 20

I'll denote alpha by & and beta by @.

& + @ = -b/a

&+@=-4/k.......eq 1

&@= c/a

&@= 4/k........eq 2

Squaring both sides of eq 1

(&+@)2= (-4/k)2

&2+@2+2&@=16/k2

24+2&@=16/k2  [from &2+@2 = 24]

Substituting the value of &@ from eq2,

24+2*4/k=16/k2

24+8/k=16/k2

24k+8/k=16/k2

24k+8=16/k2*k

24k+8=16/k

24k2+8k=16

or 24k2+8k -16

3k2+k-2

3k2+3k-2k-2

3k(k+1)-2(k+1)

(3k-2)(k+1)

Therefore,k is either 1 or 2/3

I tried my best.Sorry if there r any mistakes.

  • 7
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