If cos-1(x/2)+cos-1(y/3)=ϴ, then prove that 9x2-12xycosϴ+4y2=36sin2ϴ - Maths - Inverse Trigonometric Functions

Question

If cos-1(x/2)+cos-1(y/3)=ϴ, then
prove that
9x2-12xycosϴ+4y2=36sin2ϴ

Abhishek Kr. Jha · Accepted Answer

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If cos-1(x/2)+cos-1(y/3)=ϴ, then prove that 9x2-12xycosϴ+4y2=36sin2ϴ.

If cos^-1(x/2)+cos^-1(y/3)=ϴ, then prove that 9x²-12xycosϴ+4y²=36sin²ϴ.