If cotalphacotbeeta = 2,show that cos(alpha+beeta) /cos(alpha-beeta) =1/3 Share with your friends Share 0 Varun.Rawat answered this Solution : We have cot α . cot β = 2Now,LHS = cosα+βcosα-β=cos α . cos β - sin α . sin βcos α . cos β + sin α . sin β=cos α . cos βsin α . sin β - sin α . sin βsin α . sin βcos α . cos βsin α . sin β + sin α . sin βsin α . sin β=cot α . cot β - 1cot α . cot β + 1=2 - 12 + 1=13=RHS 1 View Full Answer
