If d is the HCF of 56 and 72 , find x,y satifiying d=56x + 72y . Also , show that x and y are not unique ....
Here is the link of the answer of the similar query:
Preceding in the same way as in the above link, you will get x=4 and y= – 3.
We can find the another values of x and y which satisfies the given equation as:
We have, 8 = 4×56 + (-3)×72 = 4×56 + (-3)×72 + 56×72 - 56×72 = (4+72)×56 + (-3-56)×72= 76×56 + (-59)×72So, (x,y) = (76,-59) is another solution.