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If one root of the quadratic equation x2-5x+6k=0 is reciprocal of other,find the value of k.

Also Find its Roots!!!!!!!!!!!!

Hi Nishranth!
Here is the answer to your query.


 
Hope! This will help you.
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  • 48
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Let the roots be a & othr 1/a

So product of zeres = a x 1/a

6k/1 =1 

k = 1/6 

  • 10

gud work

  • -16

 x2-5x+6k

Let one root be x

Therefore another root is 1/x

Now,

x2-5x+6k=0

here, a=1 b= -5 and c=6k

Now, Product of roots= x*1/x

=> c/a= 1

=> 6k/1=1

=> 1/6=k

Therefore required answer---> The value of k is 1/6

Hope it helps!!!

Cheers!

keep smiling!!

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