If one zero of polynomial (a2+9)x2+13x+6a  is reciprocal to the other, find the value of ‘a’.

Hi!
Here is the answer to your question.
 
The given quadratic polynomial is (a2 + 9) x2 + 13x + 6a.
Let one zero of the quadratic polynomial be α.
⇒ 6a = a2 + 9
a2 – 6a + 9 = 0
⇒ (a – 3)2 = 0
a – 3 = 0
a = 3
Thus, the value of a is 3.
 
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