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If point (4,3) lies on the graph of the equation 3x-ay=6. Find whether (-2,-6) also lie on the same graph. Find the coordinates of the points where the graph cuts x-axis and y-axis.

This is alo anew question faced by me. So, please Experts, help me to solve the problem and make the graph in easier way.

Thank you and reply fast

Given, the point 4,3 lies on the graph of the equation 3x-ay=6. Therefore,the point 4,3 satisfies the equation.3×4-a×3=6⇒12-3a=6⇒3a=6⇒a=2Thus, the equation will be 3x-2y=6.Now, put the point -2,-6 in above equation, we have,3×-2-2×-6=6⇒-6+12=6⇒6=6Thus, the point -2,-6 lies on the same graph.When graph cuts x-axis, put y=03x-2×0=6⇒x=2Thus, the coordinate is 2,0.And,When graph cuts y-axis, put x=03×0-2×y=6⇒y=-3Thus, the coordinate is 0,-3.
Now, to draw the graph join the point (2,0) and (0,-3), we have,

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