If sin (A + B) =cos (A - B) =root 3 /2 and A, B (A B) are acute angles, find the values of A and B . Share with your friends Share 1 Varun.Rawat answered this We have, sin A+B = 32⇒sin A+B = sin 60°⇒A + B = 60° .......1cos A-B = 32⇒cos A-B = cos 30°⇒A - B =30° .......2adding 1 and 2, we get2A = 90°⇒A = 45°Now, from 1, we getB = 60° - 45° = 15° 3 View Full Answer The Silent Guy answered this Given, sin(A + B) = √3/2 sin(A + B) = sin 60o A + B = 60o -(i) Also, cos(A - B) = √3/2 cos(A - B) = cos 30o A - B = 30o -(ii) Adding (i) and (ii), we have 2A = 90o A = 45o B = 60o - 45o = 15o So, A = 45o and B = 15o 0
