Hello, Join AC AND BD. LET THEM INTERSECT AT O (x,y) Let coordinates of D be (x1,y1) In ||gm. ABCD, Diagonals bisect each other. => OA = OC AND OB = OD. => Coordinates of mid point of AC ie. O = [ { (1+5) /2 } , {(-2 + 10) / 2} ] = (3, 4) ( BY mid point Formula,) Coordinates of mid point of BD ie. O = { (3 + x1) / 2} , { (6 + y1) /2 } = (3, 4) (BY MID POINT FORMULA ) => (3 + x1) / 2 = 3 and (6+y1) / 2 = 4 => x1 = 3 and y1 = 2 Ans :- Coordinates of point D are (3,2) Hope it helps ! Plz. thumbs up. ANURAG. Posted by Anurag Deshmukh(student)on 13/2/12 This conversation is already closed by Expert

Hello, Join AC AND BD. LET THEM INTERSECT AT O (x,y) Let coordinates of D be (x1,y1) In ||gm. ABCD, Diagonals bisect each other. => OA = OC AND OB = OD. => Coordinates of mid point of AC ie. O = [ { (1+5) /2 } , {(-2 + 10) / 2} ] = (3, 4) ( BY mid point Formula,) Coordinates of mid point of BD ie. O = { (3 + x1) / 2} , { (6 + y1) /2 } = (3, 4) (BY MID POINT FORMULA ) => (3 + x1) / 2 = 3 and (6+y1) / 2 = 4 => x1 = 3 and y1 = 2 Ans :- Coordinates of point D are (3,2) Hope it helps ! Plz. thumbs up. ANURAG. Posted by Anurag Deshmukh(student)on 13/2/12 This conversation is already closed by Expert

Hello, Join AC AND BD. LET THEM INTERSECT AT O (x,y) Let coordinates of D be (x1,y1) In ||gm. ABCD, Diagonals bisect each other. => OA = OC AND OB = OD. => Coordinates of mid point of AC ie. O = [ { (1+5) /2 } , {(-2 + 10) / 2} ] = (3, 4) ( BY mid point Formula,) Coordinates of mid point of BD ie. O = { (3 + x1) / 2} , { (6 + y1) /2 } = (3, 4) (BY MID POINT FORMULA ) => (3 + x1) / 2 = 3 and (6+y1) / 2 = 4 => x1 = 3 and y1 = 2 Ans :- Coordinates of point D are (3,2) Hope it helps ! Plz. thumbs up. ANURAG. Posted by Anurag Deshmukh(student)on 13/2/12 This conversation is already closed by Expert