if x=2y+6,then find the value of x3-8y3-36xy-216
Given:- x=2y+6
x-2y-6=0 ----------------- (1)
x3- 8y3- 216 - 36xy
= (x)3+ (-2y)3+ (-6)3-3*x*(-2y)*(-6)
=(x-2y-6) (x2+4y2+36+2xy-12y+6x)
=0 (x2+4y2+36+2xy-12y+6x) (from equation (1) )
=0
if x=2y+6,then find the value of x3-8y3-36xy-216
Given:- x=2y+6
x-2y-6=0 ----------------- (1)
x3- 8y3- 216 - 36xy
= (x)3+ (-2y)3+ (-6)3-3*x*(-2y)*(-6)
=(x-2y-6) (x2+4y2+36+2xy-12y+6x)
=0 (x2+4y2+36+2xy-12y+6x) (from equation (1) )
=0