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if x/y =3/4 then find value of 6/7 + y-x/y+x

We have, \frac{x}{y} = \frac{3}{4} \Rightarrow 3 y = 4 x \Rightarrow y = \frac{4 x}{3} Now, \frac{6}{7} + \frac{y - x}{y + x} = \frac{6}{7} + \frac{\frac{4 x}{3} - x}{\frac{4 x}{3} + x} = \frac{6}{7} + \frac{\frac{x}{3}}{\frac{7 x}{3}} = \frac{6}{7} + \frac{1}{7} = \frac{7}{7} = 1

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