in a circular table cover of radius 32 cm,a design is formed leaving an equilateral triangle ABC in the middle - Maths - Areas Related to Circles

Question

in a circular table cover of radius 32 cm,a design is formed
leaving an equilateral triangle ABC in the middle find the area of
the design (shaded region)
for the figure refer to lesson no 12 , ex-12 3 Question no 6
page no-235 of ncert
please tell the easiest way to solve it

Manmeet Singh · Accepted Answer

Radius (r) of circle = 32 cm AD is the median of

ABC The point O divides the the median AD in the ratio 2:3 So,

AD = 48 cm In Î”ABD, AB2 = AD2 + BD2

Area of equilateral triangle = $\frac{\sqrt{3}}{4} (s i d e)^{2}$ Area of equilateral triangle,

Area of circle = Ï€r2

Area of design = Area of circle âˆ’ Area of Î”ABC

in a circular table cover of radius 32 cm,a design is formed leaving an equilateral triangle ABC in the middle. find the area of the design (shaded region) for the figure refer to lesson no .12 , ex-12.3 Question no 6.. page no-235 of ncert please tell the easiest way to solve it

in a circular table cover of radius 32 cm,a design is formed leaving an equilateral triangle ABC in the middle. find the area of the design (shaded region)

for the figure refer to lesson no .12 , ex-12.3 Question no 6.. page no-235 of ncert

please tell the easiest way to solve it