In a cubic polynmial f(1)=1 , f(2)=2 ,f(3)=3 , f(4)=5, f(5)=?

plzz help

Question

In a cubic polynmial f(1)=1 , f(2)=2 ,f(3)=3 , f(4)=5,
f(5)=?
plzz help

Anuradha Sharma · Accepted Answer

Let the polynomial is, fx=ax3+bx2+cx+dSo putting the given value of x we get, a+b+c+d=1
18a+4b+2c+d=2 227a+9b+3c+d=3 364a+16b+4c+d=5
5Now here we have 4 equation and 4 variable so solving this you can getthe value of a, b, c and d and then you can find f5

In a cubic polynmial f(1)=1 , f(2)=2 ,f(3)=3 , f(4)=5, f(5)=? plzz help

In a cubic polynmial f(1)=1 , f(2)=2 ,f(3)=3 , f(4)=5, f(5)=?

plzz help