In a right triangle ABC, the perpendicular BD on the hypotenuse AC is drawn. Prove that 1) AC x AD = AB2, 2) AC x CD= BC2
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Please find below the link of the similar query as asked by you :
https://www.meritnation.com/ask-answer/question/in-the-following-figure-abd-is-a-triangle-right-angled-at/triangles/6295483
Hope this would clear your doubt !
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Regards