In the circuit -\' TO COMPARE THE EMF OF TWO CELLS USING POTENTIOMETER \' . suppose the battery is connected to \' A \' end of potentiometer , let a null deflection be obtained in galvanometer at point \' J \' . . at that state why the emf of cell becomes equal to the potential difference between the points \' A \' and \' J \' ?
how TO COMPARE THE EMF OF TWO CELLS USING POTENTIOMETER