In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.
Total mass of organic compound = 0.468 g [Given]
Mass of barium sulphate formed = 0.668 g [Given]
1 mol of BaSO4 = 233 g of BaSO4 = 32 g of sulphur
Thus, 0.668 g of BaSO4
contains
of
sulphur = 0.0917 g of sulphur
Therefore, percentage
of sulphur
= 19.59 %
Hence, the percentage of sulphur in the given compound is 19.59 %.