In the given AP : 1, 5, 9, 13, 17....... , Find which term would have 229?

1,5,9.....229

an=229

a=1

d=4

an=a+(n-1)d

229=1+(n-1)4

229=228=(n-1)4

228=(n-1)4

n-1=228

4

n-1=57

n=57+1

n=58

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an=229 ( As given)

a=1

Common diffrnce( d=4)

an=a+(n-1)d

229=1+ (n-1)4

229= 1+4n-4

229= -3 +4n

229+3=4n

232=4n

n=232/4

n=58

Hope it helpz :)

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