in the h2 o2 fuel cell, what will happen when the concentration of NaOH will be reduced and it becomes diluted?

In Alkaline fuel cell the following reactions take place..

Anode: H2 + 2 OH- →2 H2O + 2 e-
Cathode: 1/2 O2 + H2O + 2 e- →2 OH-

 

So if the concentration of NaOH is reduced, the concentration of OH- ion will get reduced and this will slow down the rate of oxidation reaction at anode. Finally the productivity of cell will get reduced.

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