multiply numerator and denominator by sec^{2}x sec^{2}x/(tanx+sec^{2}x) =sec^{2}x/(tanx+1+tan^{2}x) let tanx =t => sec^{2}x dx =dt and solve the eq.in the form of 't '. Posted by Sr(student)on 23/2/12

multiply numerator and denominator by sec^{2}x sec^{2}x/(tanx+sec^{2}x) =sec^{2}x/(tanx+1+tan^{2}x) let tanx =t => sec^{2}x dx =dt and solve the eq.in the form of 't '. Posted by Sr(student)on 23/2/12

multiply numerator and denominator by sec^{2}x sec^{2}x/(tanx+sec^{2}x) =sec^{2}x/(tanx+1+tan^{2}x) let tanx =t => sec^{2}x dx =dt and solve the eq.in the form of 't '. Posted by Sr(student)on 23/2/12

some mistake in ur suggestion, when you multiply & divide sec^{2 }x u will get it as sec^{2} x/(tan xsec x+sec^{3 }x) dx. but, exact answer is too long and still many of them didn 't solve.!!!!!! Posted by Subin Thekkan(student)on 5/3/12

some mistake in ur suggestion, when you multiply & divide sec^{2 }x u will get it as sec^{2} x/(tan xsec x+sec^{3 }x) dx. but, exact answer is too long and still many of them didn 't solve.!!!!!! Posted by Subin Thekkan(student)on 5/3/12

some mistake in ur suggestion, when you multiply & divide sec^{2 }x u will get it as sec^{2} x/(tan xsec x+sec^{3 }x) dx. but, exact answer is too long and still many of them didn 't solve.!!!!!! Posted by Subin Thekkan(student)on 5/3/12

convery in sin and cos form- cosx/(1+sinx cosx) then rationalise. it will be ((cosx/(1-sin^2x cos^2x) - (cos^2x sinx/(1-cos^2x sin^2x)) then put sinx=t in one part and cosx = t in other. solve as usual.. Posted by Sana(student)on 14/2/13

convery in sin and cos form- cosx/(1+sinx cosx) then rationalise. it will be ((cosx/(1-sin^2x cos^2x) - (cos^2x sinx/(1-cos^2x sin^2x)) then put sinx=t in one part and cosx = t in other. solve as usual.. Posted by Sana(student)on 14/2/13

convery in sin and cos form- cosx/(1+sinx cosx) then rationalise. it will be ((cosx/(1-sin^2x cos^2x) - (cos^2x sinx/(1-cos^2x sin^2x)) then put sinx=t in one part and cosx = t in other. solve as usual.. Posted by Sana(student)on 14/2/13