Integrate : ex(x2+1/(x+1)2)dx Share with your friends Share 42 Manbar Singh answered this Let I = ∫exx2 + 1x+12 dx=∫exx2 - 1 + 2x+12 dx=∫ex x+1x-1 + 2x+12 dx=∫exx-1x+1 dx + 2∫exx+12 dx=x-1x+1 × ∫ex dx - ∫ddxx-1x+1 ×∫ex dx dx + 2∫exx+12 dx=x-1x+1 ex - ∫x+1×1 - x-1×1x+12 ex dx + 2∫exx+12 dx=exx-1x+1 -2∫exx+12 dx + 2∫exx+12 dx=exx-1x+1 + C 119 View Full Answer