integration of cos​4x

∫cos4x dx
= cos2x * cos2x  dx
= (1-sin2x)cos2x  dx
=  cos2x dx -  sin2x cos2x dx
= 1/2( cos2x+1)dx -  1/4 (4sin2x cos2x dx)                 cos2x= 2cos2x - 1   cos2x = 1/2 (cos2x+1)
= 1/2 cos2x dx + 1/2 1 dx  - 1/4[sin22x dx]
=  1/4 sin2x + x/2 - 1/8[1-cos4x dx]                           cos2x=1-  2sin2x       sin^2 x=1/2(1-cos2x)                 
=  1/4 sin2x + x/2 - 1/8 dx + 1/8 cos4x dx
=  1/4 sin2x + x/2 - x/8 + 1/32 sin4x + C
=  1/32 sin4x + 1/4 sin2x + 3x/8 + C

 
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