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integration of X2+4/X4+16

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Int, [(x2+4)/(x2+16)]

=​Int, [(x2+16-12)/(x2+16)]

= Int. [(​(x2+16)/(x2+16) - (12)/​(x2+16)]

= Int. [1 -​(12)/​(x2+16)]

= Int. (1) - 12 *Int. [1/​(x2+16)]

= x - 12[(1/4)Tan-1(x/4)] + c

= x - 3Tan-1(x/4)] + c

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Hope it helped.
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