Let 's assume 68 is a term a_{n} = 68 a = 7 d = 10 - 7 = 3 a_{n} = a + (n - 1) d 68 = 7 + (n - 1) 3 61 = (n - 1) 3 n - 1 = 20.33 n = 21.33 Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13.... Posted by Rosy Got U Agyn...(student)on 6/12/13 This conversation is already closed by Expert

Let 's assume 68 is a term a_{n} = 68 a = 7 d = 10 - 7 = 3 a_{n} = a + (n - 1) d 68 = 7 + (n - 1) 3 61 = (n - 1) 3 n - 1 = 20.33 n = 21.33 Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13.... Posted by Rosy Got U Agyn...(student)on 6/12/13 This conversation is already closed by Expert

Let 's assume 68 is a term a_{n} = 68 a = 7 d = 10 - 7 = 3 a_{n} = a + (n - 1) d 68 = 7 + (n - 1) 3 61 = (n - 1) 3 n - 1 = 20.33 n = 21.33 Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13.... Posted by Rosy Got U Agyn...(student)on 6/12/13 This conversation is already closed by Expert

Let 's assume 68 is a term a_{n} = 68a = 7d = 10 - 7 = 3a_{n} = a + (n - 1) d68 = 7 + (n - 1) 361 = (n - 1) 3n - 1 = 20.33n = 21.33Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13.... Posted by Rosy Got U Agyn...(student)on 6/12/13

Let 's assume 68 is a term a_{n} = 68a = 7d = 10 - 7 = 3a_{n} = a + (n - 1) d68 = 7 + (n - 1) 361 = (n - 1) 3n - 1 = 20.33n = 21.33Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13.... Posted by Rosy Got U Agyn...(student)on 6/12/13

Let 's assume 68 is a term a_{n} = 68a = 7d = 10 - 7 = 3a_{n} = a + (n - 1) d68 = 7 + (n - 1) 361 = (n - 1) 3n - 1 = 20.33n = 21.33Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13.... Posted by Rosy Got U Agyn...(student)on 6/12/13