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Let 's assume 68 is a term a_{n} = 68a = 7d = 10 - 7 = 3a_{n} = a + (n - 1) d68 = 7 + (n - 1) 361 = (n - 1) 3n - 1 = 20.33n = 21.33Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13....

Posted by Nawty Rosy(student), on 6/12/13

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Let 's assume 68 is a term

a_{n} = 68

a = 7

d = 10 - 7 = 3

a_{n} = a + (n - 1) d

68 = 7 + (n - 1) 3

61 = (n - 1) 3

n - 1 = 20.33

n = 21.33

Since n is not a whole number and the number of terms cannot be in decimals, 68 is not a term of the AP 7 , 10, 13....

Posted by Nawty Rosy(student), on 6/12/13

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