** O GIRL! OUT OF A GROUP OF SWANS ,7/2 TIMES THE SQUARE ROOT OF THE NUMBER ARE PLAYING ON THE SHORE OF A TANK.THE 2 REMIING ONES ARE PLAYING ,WITH AMOROUS FIGHT,IN THE WATER. WHAT IS THE TOTAL NO OF SWANS? **

** {HINT:-X=Y^{2}}. **

Asked by Vangara Aditya(student), on 21/9/09

#### Answers

Let the totoal no. of swans be x

x - 7/2 root x =2

y^{2}-7/2 y =2 (x =y^{2})

2y^{2}-7y =4

2y^{2}-7y-4=0

2y^{2} -8y +y -4 =0

2y(y-4)+1(y-4)=0

(2y+1)(y-4)=0

so y=4

i.e. x=16

so total no. of swans are 16

Posted by Kanwar Preet(student), on 21/9/09

thumbs up plzzzzzzzzzzzzz

Posted by Kanwar Preet(student), on 21/9/09

if I am not wrong....

this is an ncert example sum....

it was my most fav question

;)

Posted by Tanoy Bose(student), on 21/9/09

but what is "y"

Posted by Akshat Gupta(student), on 13/3/13

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