o is the centre of the circle .PA AND PB ARE TANGENTS OF THE CIRCLE FRMEXTERIOR POINT P. PROVE THAT PAOB IS CYCLIC QUADRILATERAL Share with your friends Share 0 Pooja Khanna answered this Follow the given link for similar query: https://www.meritnation.com/ask-answer/question/o-is-the-centre-of-a-circle-pa-pb-are-tangents-segments-s/circles/3811554 0 View Full Answer Adarsh answered this In this questionanglePAO=90anglePBO=90 So PAO + PBO =180So AOB + APB = 360 - [PAO + PBO]AOB+APB=360 - 1802.AOB +APB=180from 1 and 2Opposite angles of quadrilateral are suuplementary.So it is a cyclic quadrilateral. -1