o is the centre of the circle .PA AND PB ARE TANGENTS OF THE CIRCLE FRMEXTERIOR POINT P. PROVE THAT PAOB IS CYCLIC QUADRILATERAL

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In this question
anglePAO=90
anglePBO=90
  1. So PAO + PBO =180
So AOB + APB = 360 - [PAO + PBO]
AOB+APB=360 - 180
2.AOB +APB=180
from 1 and 2
Opposite angles of quadrilateral are suuplementary.
So it is a cyclic quadrilateral.
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