obtain all the zeroes of 3x4-14x2+8 if two of its zeroes we root 2/3 and root -2/3.

here x4 is x raise to 4 and x2 is square

Let, px=3x4-14x2+8              =3x4-12x2-2x2+8              =3x2x2-4-2x2-4              =x2-43x2-2To find the zeroes of polynomial px, put px=0Therefore,x2-43x2-2=0x2-4=0 and 3x2-2=0x2=4 and x2=23x=±2 and x=±23Hence, other two zeroes are 2 and -2.

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