P and Q are respectively points on the Ab and AC of Triangle ABC.If AP=2cm,PB=4cm,AQ=3cm and QC=6cm,prove that BC=3PQ.
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Given: AP = 2 cm, PB = 4 cm , AQ = 3 cm and QC = 6 cm
AB = AP + PB = 2+4=6 cm
AC = AQ + QC = 3+6=9 cm
in the triangles APQ and ABC,
and
the ratio of the two corresponding sides are equal and angle contained by these two sides are equal.
therefore
by the similarity rule: