Please explain me how to solve this question, please.......... faaaast........

THE VALUE OF (1-1/3) (1-1/4) (1-1/5) (1-1/6) .....(1-1/n) IS ________.

If you answer this i will give you.

The given expression is ,

                    =    (1 - 1/3)(1 - 1/4)(1 - 1/5).....(1 - 1/n)

                    =  (2/3) * (3/4) *(4/5) * ........ (n-2)/(n-1)*(n-1)/n 

 Now you can observe that 3 is cancelled out in first two term and then 4 is being cancelled out in 3rd and 4th term and      so on  and at the end 2 of the first term and n of the last term will reamain so finally,

                     =  (2/3) * (3/4) *(4/5) * ........ (n-2)/(n-1)*(n-1)/n 
 
                       = 2/n  (answer)