Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre of the circle.
Hi Rida
Draw a circle with centre O.
draw a tangent PR touching circle at P.
Draw QP perpendicular to RP at point P, Qp lies in the circle.
Now, angle OPR = 90 degree (radius perpendicular to tangent)
also angle QPR = 90 degree (given)
Therefore angle OPR = angle QPR. This is possible only when O lies on QP. Hence, it is proved that the perpendicular at the point of contact to the tangent to a circle passes through the centre.
draw a tangent PR touching circle at P.
Draw QP perpendicular to RP at point P, Qp lies in the circle.
Now, angle OPR = 90 degree (radius perpendicular to tangent)
also angle QPR = 90 degree (given)
Therefore angle OPR = angle QPR. This is possible only when O lies on QP. Hence, it is proved that the perpendicular at the point of contact to the tangent to a circle passes through the centre.
Cheers
Best of luck for your exams